9x^2-9(p+q)x+(2p^2+5pq+2q^2)=0

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Solution for 9x^2-9(p+q)x+(2p^2+5pq+2q^2)=0 equation: 


Simplifying
9x2 + -9(p + q) * x + (2p2 + 5pq + 2q2) = 0

Reorder the terms for easier multiplication:
9x2 + -9x(p + q) + (2p2 + 5pq + 2q2) = 0
9x2 + (p * -9x + q * -9x) + (2p2 + 5pq + 2q2) = 0
9x2 + (-9px + -9qx) + (2p2 + 5pq + 2q2) = 0

Reorder the terms:
9x2 + -9px + -9qx + (5pq + 2p2 + 2q2) = 0

Remove parenthesis around (5pq + 2p2 + 2q2)
9x2 + -9px + -9qx + 5pq + 2p2 + 2q2 = 0

Reorder the terms:
5pq + -9px + 2p2 + -9qx + 2q2 + 9x2 = 0

Solving
5pq + -9px + 2p2 + -9qx + 2q2 + 9x2 = 0

Solving for variable 'p'.

The solution to this equation could not be determined.

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